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det| 10 7 ; 5 11 | = 75
5α² + 3α + 7 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
11ω² + 1ω + 5 = 0
N₂ + 3H₂ ⇌ 2NH₃
\frac{9}{1} \sum_{i=1}^{n} i^{2}
1φ² + 6φ + 3 = 0
e^{i\pi} + 1 = 0
e^{i\pi} + 1 = 0
det| 4 6 ; 1 5 | = 14
d/dθ [θ^1] = 1θ^0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
F = G m₁m₂ / r²
det| 11 8 ; 6 12 | = 84
\binom{n}{k} = \frac{n!}{k!(n-k)!}
F = ma
iħ ∂ψ/∂t = Ĥψ
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\frac{12}{3} \sum_{i=1}^{n} i^{2}
4φ² + 5φ + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
ΔS ≥ 0
iħ ∂ψ/∂t = Ĥψ
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
e^{i\pi} + 1 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
CaCO₃ → CaO + CO₂
iħ ∂ψ/∂t = Ĥψ
2H₂ + O₂ → 2H₂O
det| 11 4 ; 4 12 | = 116
det| 1 1 ; 1 2 | = 1
ω = 2πf
∫₀^∞ e^(-n²) dn = √π / 2
PV = nRT
ω = 2πf
e^{i\pi} + 1 = 0
det| 3 2 ; 3 4 | = 6
det| 4 8 ; 2 5 | = 4
\oint_C \vec{F}\cdot d\vec{r} = 0
∫₀^∞ e^(-x²) dx = √π / 2
∂φ/∂γ = 8φ
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{7}{7} \sum_{i=1}^{n} i^{2}
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 10 3 ; 1 11 | = 107
∑_{k=1}^{n} k = n(n+1)/2
∇²x = 0
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-n²) dn = √π / 2
5t² + 7t + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
CaCO₃ → CaO + CO₂
λ = h/p
F = ma
det| 11 8 ; 7 12 | = 76
1ψ² + 1ψ + 7 = 0
11z² + 9z + 3 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
Fe₂O₃ + 3CO → 2Fe + 3CO₂
e^{i\pi} + 1 = 0
det| 10 1 ; 5 11 | = 105
det| 6 6 ; 7 7 | = 0
∇²β = 0
N₂ + 3H₂ ⇌ 2NH₃
2H₂ + O₂ → 2H₂O
11β² + 8β + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
N₂ + 3H₂ ⇌ 2NH₃
ω = 2πf
det| 8 3 ; 5 9 | = 57
\oint_C \vec{F}\cdot d\vec{r} = 0
12ω² + 5ω + 6 = 0
4t² + 7t + 3 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 6 3 ; 7 7 | = 21
e^{i\pi} + 1 = 0
det| 2 7 ; 5 3 | = -29
3ψ² + 2ψ + 6 = 0
N₂ + 3H₂ ⇌ 2NH₃
ΔS ≥ 0
d/dz [z^12] = 12z^11
∫₀^∞ e^(-ω²) dω = √π / 2
det| 1 9 ; 6 2 | = -52
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 6 ; 6 8 | = 20
1t² + 1t + 0 = 0